$\begin{align}  & \cos {{53}^{\circ }}=0/6\Rightarrow \sin {{53}^{\circ }}=\sqrt{1-{{\cos }^{2}}{{53}^{\circ }}} \\  & \Rightarrow \sin {{53}^{\circ }}=\sqrt{1-{{(0/6)}^{2}}}=\sqrt{1-0/36}=\sqrt{0/64} \\  & \Rightarrow \sin {{53}^{\circ }}=0/8 \\  & \Rightarrow {{S}_{_{ABC}^{\Delta }}}=\frac{1}{2}BA\times BC\times \sin {{53}^{\circ }}=\frac{1}{2}\times 2\times 5\times 0/8=4 \\ \end{align}$