$u=\frac{1}{2}c{{v}^{2}}=\frac{1}{2}\times 660\times {{10}^{-4}}\times {{(330)}^{2}}=35/9j\to p=\frac{u}{t}=\frac{35/9}{1\times {{10}^{-2}}}\simeq 3/6\times {{10}^{4}}=36kv$