اگر $f(x)=\left| x \right|$ و $g(x)={{x}^{۲}}+۲x+۱$، آنگاه حاصل $(fog)(۱-\sqrt{۲})-(gof)(۱-\sqrt{۲})$، کدام است؟
$\begin{align} & f(x)=\left| x \right|\,\,\,\,,\,\,\,\,\,g(x)={{x}^{2}}+2x+1={{(x+1)}^{2}} \\ & (fog)(1-\sqrt{2})-(gof)(1-\sqrt{2}) \\ & =f(g(1-\sqrt{2}))-g(f(1-\sqrt{2})) \\ & =f({{(1-\sqrt{2}+1)}^{2}})-g(\overbrace{\left| 1-\sqrt{2} \right|}^{-}) \\ & =f({{(2-\sqrt{2})}^{2}})-g(\sqrt{2}-1) \\ & =\left| 4+2-4\sqrt{2} \right|-{{(\sqrt{2}-1+1)}^{2}} \\ & =\overbrace{\left| 6-4\sqrt{2} \right|}^{+}-2=6-4\sqrt{2}-2=4(1-\sqrt{2}) \\ \end{align}$