${{t}_{1}}=\frac{1}{6}s\Rightarrow {{\Phi }_{1}}=0/04\cos (2\pi \times \frac{1}{6})=0/04\cos \frac{\pi }{3}=0/02Wb$ ${{t}_{2}}=\frac{1}{2}s\Rightarrow {{\Phi }_{2}}=0/04\cos (2\pi \times \frac{1}{2})=-0/04Wb$ $\left| \overline{\varepsilon } \right|=\left| -N\frac{\Delta \Phi }{\Delta t} \right|=\left| -100\times \frac{-0/04-0/02}{\frac{1}{2}-\frac{1}{6}} \right|=\left| -100\times (-0/18) \right|=18V$ $\overline{I}=\frac{\overline{\varepsilon }}{R}=\frac{18}{6}=3A$