$f\left( x \right)=\sqrt[m]{{{u}^{n}}}\to {f}'\left( x \right)=\frac{n{u}'}{m\sqrt[m]{{{u}^{m-1}}}}$ $y=\sqrt[5]{2{{x}^{3}}}\Rightarrow {y}'=\frac{{{\left( 2{{x}^{3}} \right)}^{\prime }}}{5\sqrt[5]{{{\left( 2{{x}^{3}} \right)}^{4}}}}=\frac{3\times 2\times {{x}^{3-1}}}{5\sqrt[5]{{{2}^{4}}\times {{\left( {{x}^{3}} \right)}^{4}}}}=\frac{6{{x}^{2}}}{5\sqrt[5]{16{{x}^{12}}}}$