$\sqrt{169-{{x}^{2}}}=x-17$  $\left\{ \begin{align}  & 169-{{x}^{2}}\ge 0\Rightarrow 169\ge {{x}^{2}}\Rightarrow -13\le x\le 13 \\  & x-17\ge 0\Rightarrow x\ge 17 \\ \end{align} \right.\begin{matrix}   (1)  \\   (2)  \\ \end{matrix}\xrightarrow{(1)\bigcap (2)}\varnothing $