$ 3-\frac{1}{3+\frac{1}{1-\frac{3}{2}}} = 3-\frac{1}{3+\frac{1}{-\frac{1}{2}}} = 3-\frac{1}{3-2}=3 - \frac{1}{1}=2 $ صورت کسر $ \frac{4}{4-\frac{4}{4+\frac{4}{3}}}+1 = \frac{4}{4-\frac{4}{\frac{16}{3}}}+1 = \frac{4}{4-\frac{12}{16}}+1 = \frac{4}{\frac{13}{4}}+1=\frac{16}{13}+1=\frac{29}{13} $مخرج کسر $ D=\frac{2}{\frac{29}{13}}-1=\frac{26}{29}-1=-\frac{3}{29} $