$\log _9^x = \frac{3}{2} \Rightarrow x = {\left( 9 \right)^{\frac{3}{2}}} \Rightarrow x = {\left( {{3^2}} \right)^{\frac{3}{2}}} \Rightarrow x = {3^3}$$x = {3^{ - 3}}$$\log _3^{{3^{ - 3}}} =  - 3$