$_{{{\theta }_{2}}=3\theta \Rightarrow \Delta {{\theta }_{2}}={{\theta }_{2}}-\theta =2\theta {{(}^{\circ }}C)=2\theta (K)}^{{{\theta }_{1}}=2\theta \Rightarrow \Delta {{\theta }_{1}}={{\theta }_{1}}-\theta =\theta {{(}^{\circ }}C)=\theta (K)}$  از آن‌جایی که فرایندها، هم‌حجم هستند، داریم: $\frac{{{Q}_{2}}}{{{Q}_{1}}}=\frac{{{n}_{2}}{{C}_{v}}\Delta {{\theta }_{2}}}{{{n}_{1}}{{C}_{v}}\Delta {{\theta }_{1}}}\xrightarrow{{{n}_{1}}={{n}_{2}}}\frac{{{Q}_{2}}}{{{Q}_{1}}}=\frac{\Delta {{\theta }_{2}}}{\Delta {{\theta }_{1}}}=\frac{2\theta }{\theta }=2$