$\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}\to \frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{2}{3} \right)}^{2}}=\frac{4}{9}\to {{E}_{1}}=\frac{9}{4}{{E}_{2}}\xrightarrow{{{E}_{1}}-{{E}_{2}}=250}{{E}_{2}}=200$