اگر $f\left( ۰ \right)=۲$ و ${f}'\left( ۰ \right)=-۱$ و $g\left( ۰ \right)=۱$ و ${g}'\left( ۰ \right)=-۳$ باشد. مقدار مشتق $\frac{f}{g}$ به ازای $x=۰$ کدام است؟
$h\left( x \right)=\frac{f\left( x \right)}{g\left( x \right)}\to {h}'\left( x \right)=\frac{{f}'\left( x \right).g\left( x \right)-{g}'\left( x \right).f\left( x \right)}{{{\left( g\left( x \right) \right)}^{2}}}$ ${{\left( \frac{f}{g} \right)}^{\prime }}\left( 0 \right)=\frac{{f}'\left( 0 \right).g\left( 0 \right)-{g}'\left( 0 \right).f\left( 0 \right)}{{{\left( g\left( 0 \right) \right)}^{2}}}=\frac{\left( -1 \right)\left( 1 \right)-\left( -3 \right)\left( 2 \right)}{{{1}^{2}}}=\frac{-1+6}{1}=5$