$\overline{I}=\frac{\overline{\varepsilon }}{R}\Rightarrow \overline{\varepsilon }=\overline{I}\times R=0/02\times 8=0/16V$ $\left| \overline{\varepsilon } \right|=\left| -N\frac{\Delta \Phi }{\Delta t} \right|\xrightarrow{\frac{\Delta \Phi }{\Delta t}=}$ آهنگ تغییر شار $\frac{\Delta \Phi }{\Delta t}=\frac{\overline{\varepsilon }}{N}=\frac{0/16}{200}=8\times {{10}^{-4}}\frac{Wb}{s}$