$\begin{align}  & F=qE\ \ \to \ \ 1/6\times {{10}^{-15}}=1/6\times {{10}^{-19}}\times E\ \ \to \ \ E={{10}^{4}}N/C \\  & \Delta V=Ed={{10}^{4}}\times (10\times {{10}^{-2}})\ \ \to \ \ \Delta V={{10}^{3}}V \\ \end{align}$