اگر $x=\sqrt[۳]{{{(\sqrt[۷]{۳})}^{۲۰}}}$ باشد، حاصل $\frac{\sqrt[۵]{{{x}^{۷}}}\times \sqrt{x}}{{{x}^{۳}}}$ کدام است؟
$\begin{align} & x=\sqrt[3]{{{(\sqrt[7]{3})}^{20}}}=\sqrt[3]{\sqrt[7]{{{3}^{20}}}}=\sqrt[21]{{{3}^{20}}}={{3}^{\frac{20}{21}}} \\ & \left\{ \begin{matrix} \sqrt[5]{{{x}^{7}}}=\sqrt[5]{{{({{3}^{\frac{20}{21}}})}^{7}}}=\sqrt[5]{{{3}^{\frac{20\times 7}{21}}}}=\sqrt[5]{{{3}^{\frac{20}{3}}}}={{3}^{\frac{20}{3}\times \frac{1}{5}}}={{3}^{\frac{20}{15}}}={{3}^{\frac{4}{3}}} \\ \sqrt{x}=\sqrt{{{3}^{\frac{20}{21}}}}={{3}^{\frac{20}{21}\times \frac{1}{2}}}={{3}^{\frac{10}{21}}} \\ {{x}^{3}}={{({{3}^{\frac{20}{21}}})}^{3}}={{3}^{\frac{20\times 3}{21}}}={{3}^{\frac{20}{7}}} \\\end{matrix} \right. \\ & \Rightarrow hasel=\frac{{{3}^{\frac{4}{3}}}\times {{3}^{\frac{10}{21}}}}{20}=\frac{{{3}^{\frac{28+10}{21}}}}{20}=\frac{{{3}^{\frac{38}{21}}}}{20}={{3}^{\frac{38}{21}-\frac{20}{7}}}={{3}^{\frac{38-60}{21}}}={{3}^{-\frac{22}{21}}} \\ \end{align}$