${{C}_{6}}{{H}_{12}}{{O}_{6}}(aq)\to 2{{C}_{2}}{{H}_{5}}OH(aq)+2C{{O}_{2}}(g);\,{{C}_{2}}{{H}_{5}}OH=46g\,mo{{l}^{-1}}$ $?{{m}^{3}}CO={{10}^{6}}g\,{{C}_{2}}{{H}_{5}}OH\times \frac{1mol\,{{C}_{2}}{{H}_{5}}OH}{46g\,{{C}_{2}}{{H}_{5}}OH}\times \frac{2mol\,C{{O}_{2}}}{2mol\,{{C}_{2}}{{H}_{5}}OH}\times \frac{22/4L\,C{{O}_{2}}}{1mol\,C{{O}_{2}}}\times \frac{1{{m}^{3}}}{1000L}\simeq 487{{m}^{3}}C{{O}_{2}}$