$\frac{{\mathop {\cancel{{0/0072}}}\limits^{0/09}  \times {{10}^x}}}{{\mathop {\cancel{{0/08}}}\limits_1  \times {{10}^y}}} = 9 \times {10^6} \Rightarrow \frac{{0/09 \times {{10}^x}}}{{{{10}^y}}} = 0/09 \times {10^{x - y}}$ $ \Rightarrow 9 \times {10^{x - y - 2}} = 9 \times {10^6} \Rightarrow x - y - 2 = 6 \Rightarrow x - y = 8$ $x = 2y$ طبق فرض $ \to 3y - y = 8 \Rightarrow y = 4,x = 12$ بنابراین: $x + y = 16$