$\left| 2x-{{x}^{2}} \right|=\text{ }\!\!~\!\!\text{ }\left\{ \begin{matrix} 2x-{{x}^{2}},2x-{{x}^{2}}\ge 0,x(2-x)\ge 0  \\ {{x}^{2}}-2x,2x-{{x}^{2}}\lt 0,x(2-x) \lt 0  \\ \end{matrix} \right.\text{ }\!\!~\!\!\text{  }$      بنابراین: $\left| 2x-{{x}^{2}} \right|=\left\{ \begin{matrix} 2x-{{x}^{2}},0\le x\le 2  \\ {{x}^{2}}-2x,x\lt 0,x\gt 2  \\ \end{matrix} \right.$   $2x-{{x}^{2}}+{{x}^{2}}-2x=0,0\le x\le 2$ ${{x}^{2}}-2x+{{x}^{2}}-2x=0\Rightarrow 2{{x}^{2}}-4x=0,x\lt 0,x\gt 2$   $2x(x-2)=0\Rightarrow \left\{ \begin{matrix} x=0 (ق ق غ) \\ x=2  \\ \end{matrix} \right.$