جواب کلی معادلهٔ مثلثاتی $\frac{۳}{۲}\cos x-{{\sin }^{۲}}x=۰$ کدام است؟
$\begin{align} & \frac{3}{2}\cos x-{{\sin }^{2}}x=\frac{3}{2}\cos x-(1-{{\cos }^{2}}x)=0 \\ & \Rightarrow 2{{\cos }^{2}}x+3\cos x-2=0 \\ & \Rightarrow \cos x=\frac{-3\pm \sqrt{25}}{4}=\frac{-3\pm 5}{4} \\ & \Rightarrow \left\{ \begin{matrix} \cos x=-2\,\,\,nadorost \\ \cos x=\frac{1}{2} \\\end{matrix} \right. \\ & \Rightarrow \cos x=\frac{1}{2}=\cos \frac{\pi }{3}\Rightarrow x=2k\pi \pm \frac{\pi }{3} \\ \end{align}$